3 Smoothness and differentials
April 29,
2019
General reference: [ GW ] Ch. 6.
The Zariski tangent space
If in the above setting the ideal ${\mathfrak m}$ is finitely generated, then $\dim _{\kappa (x)} T_xX$ is the minial number of elements needed to generate ${\mathfrak m}$ and in particular is finite.
The tangent space construction if functorial in the following sense: Given a scheme morphism $f\colon X\to Y$ and $x\in X$ such that $\dim _{\kappa (x)}T_xX$ is finite or $[\kappa (x) : \kappa (f(x)) ]$ is finite, then we obtain a map
\[ df_x \colon T_xX \to T_{f(x)} Y \otimes _{\kappa (f(x))} \kappa (x). \]
Smooth morphisms
A morphism $f\colon X\to Y$ of schemes is called smooth of relative dimension $d\ge 0$ in $x\in X$, if there exist affine open neighborhoods $U \subseteq X$ of $x$ and $V=\operatorname{Spec}R\subseteq Y$ of $f(x)$ such that $f(U) \subseteq V$ and an open immersion $j \colon U \to \operatorname{Spec}R[T_1, \dots , T_n](f_1, \dots , f_{n-d})$ such that the triangle
is commutative, and that the Jacobian matrix $J_{f_1, \dots , f_{n-d}}(x)$ has rank $n-d$.
We say that $f\colon X\to Y$ is smooth of relative dimension $d$ if $f$ is smooth of relative dimension $d$ at every point of $X$. Instead of smooth of relative dimension $0$, we also use the term étale.
With notation as above, if $f$ is smooth at $x\in X$, then $x$ as an open neighborhood such that $f$ is smooth at all points of this open neighborhood. Clearly, $\mathbb {A}^n_S$ and $\mathbb {P}^n_S$ are smooth of relative dimension $n$ for every scheme $S$. (It is harder to give examples of non-smooth schemes directly from the definition; we will come back to this later.)
May 6,
2019
Recall from commutative algebra that for a ring $R$ we define the (Krull) dimension $\dim R$ of $R$ as the supremum over all lengths of chains of prime ideals, or equivalently as the dimension of the topological space $\operatorname{Spec}R$ in the sense of the following definition.
We will use this notion of dimension for non-affine schemes, as well. Recall the following theorem about the dimension of finitely generated algebras over a field from commutative algebra:
By passing to an affine cover, we obtain the following corollary:
Let $k$ be a field.
Let $X$ be an integral $k$-scheme of finite type. Assume that $K(X)\cong k(T_1, \dots , T_d)[\alpha ]$ with $\alpha $ separable algebraic over $k(T_1, \dots , T_d)$. (This is always possible if $k$ is perfect.) (Then $\dim X=d$ by the above.)
Then there exists a dense open subset $U\subseteq X$ and a separable irreducible polynomial $g \in k(T_1,\dots , T_d)[T]$ with coefficients in $k[T_1,\dots , T_d]$, such that $U$ is isomorphic to a dense open subset of $\operatorname{Spec}k[T_1,\dots T_d]/(g)$.
May 8,
2019
For references to the literature, see [ GW ] App. B, in particular B.73, B.74, B.75
One can show that the inequality $\dim A \le \dim _\kappa {\mathfrak m}/{\mathfrak m}^2$ always holds. Therefore we can rephrase the definition as saying that $A$ is regular if ${\mathfrak m}$ has a generating system consisting of $\dim A$ elements.
We quote the following (mostly non-trivial) results about regular rings:
Every localization of a regular ring is regular.
If $A$ is regular, then the polynomial ring $A[T]$ is regular.
(Theorem of Auslander–Buchsbaum) Every regular local ring is factorial.
Let $A$ be a regular local ring with maximal ideal ${\mathfrak m}$ and of dimension $d$, and let $f_1,\dots , f_r\in {\mathfrak m}$. Then $A/(f_1, \dots , f_r)$ is regular of dimension $d-r$ if and only if the images of the $f_i$ in ${\mathfrak m}/{\mathfrak m}^2$ are linearly independent over $A/{\mathfrak m}$.
Let $k$ be a field.
The morphism $X\to \operatorname{Spec}k$ is smooth of relative dimension $d$ at $x$.
For all points $\overline{x}\in X_K$ lying over $x$, $X_K$ is smooth over $K$ of relative dimension $d$ at $\overline{x}$.
There exists a point $\overline{x}\in X_K$ lying over $x$, such that $X_K$ is smooth over $K$ of relative dimension $d$ at $\overline{x}$.
For all points $\overline{x}\in X_K$ lying over $x$, the local ring ${\mathscr O}_{X_K,\overline{x}}$ is regular of dimension $d$.
There exists a point $\overline{x}\in X_K$ lying over $x$, such that the local ring ${\mathscr O}_{X_K,\overline{x}}$ is regular of dimension $d$.
May 13,
2019
Let $X = V(g_1, \dots , g_s)\subseteq \mathbb {A}^n_k$ and let $x\in X$ be a smooth closed point. Let $d=\dim {\mathscr O}_{X,x}$. Then $J_{g_1, \dots , g_s}(x)$ has rank $n-d$. In particular, $s\ge n-d$.
After renumbering the $g_i$, if necessary, there exists an open neighborhood $U$ of $x$ and an open immersion $U \subseteq V(g_1, \dots , g_{n-d})$, i.e., locally around $x$, “$X$ is cut out in affine space by the expected number of equations”.
$X$ is smooth over $k$.
$X\otimes _kL$ is regular for every field extension $L/k$.
There exists an algebraically closed extension field $K$ of $k$ such that $X\otimes _kK$ is regular.
The sheaf of differentials
General references: [ M2 ] §25, [ Bo ] Ch. 8, [ H ] II.8.
Let $A$ be a ring.
(Leibniz rule) $D(bb’) = bD(b’) + b’D(b)$ for all $b, b’\in B$,
$d(a) = 0$ for all $a\in A$.
Assuming property (a), property (b) is equivalent to saying that $D$ is a homomorphism of $A$-modules. We denote the set of $A$-derivations $B\to M$ by $\operatorname{Der}_A(B, M)$; it is naturally a $B$-module.
Let $B$ be an $A$-algebra. We call a $B$-module $\Omega _{B/A}$ together with an $A$-derivation $d_{B/A}\colon B\to \Omega _{B/A}$ a module of (relative, Kähler) differentials of $B$ over $A$ if it satisfies the following universal property:
For every $B$-module $M$ and every $A$-derivation $D\colon B\to M$, there exists a unique $B$-module homomorphism $\psi \colon \Omega _{B/A}\to M$ such that $D = \psi \circ d_{B/A}$.
In other words, the map $\operatorname{Hom}_B(\Omega _{B/A}, M) \to \operatorname{Der}_A(B, M)$, $\psi \mapsto \psi \circ d_{B/A}$ is a bijection.
Let $I$ be a set, $B= A[T_i, i\in I]$ the polynomial ring. Then $\Omega _{B/A} := B^{(I)}$ with $d_{B/A}(T_i) = e_i$, the “$i$-th standard basis vector” is a module of differentials of $B/A$.
So we can write $\Omega _{B/A} = \bigoplus _{i\in I} Bd_{B/A}(T_i)$.
May 15,
2019
We will see later that for a scheme morphism $X\to Y$, one can construct an ${\mathscr O}_X$-module $\Omega _{X/Y}$ together with a “derivation” ${\mathscr O}_X\to \Omega _{X/Y}$ by gluing sheaves associated to modules of differentials attached to the coordinate rings of suitable affine open subschemes of $X$ and $Y$.
Let $\varphi \colon A\to B$ be a ring homomorphism. For the next definition, we will consider the following situation: Let $C$ be a ring, $I\subseteq C$ an ideal with $I^2 = 0$, and let
be a commutative diagram (where the right vertical arrow is the canonical projection). We will consider the question whether for these data, there exists a homomorphism $B\to C$ (dashed in the following diagram) making the whole diagram commutative:
We say that $\varphi $ is formally unramified, if in every situation as above, there exists at most one homomorphism $B\to C$ making the diagram commutative.
We say that $\varphi $ is formally smooth, if in every situation as above, there exists at least one homomorphism $B\to C$ making the diagram commutative.
We say that $\varphi $ is formally étale, if in every situation as above, there exists a unique homomorphism $B\to C$ making the diagram commutative.
Passing to the spectra of these rings, we can interpret the situation in geometric terms: $\operatorname{Spec}C/I$ is a closed subscheme of $\operatorname{Spec}C$ with the same topological space, so we can view the latter as an “infinitesimal thickening” of the former. The question becomes the question whether we can extend the morphism from $\operatorname{Spec}C/I$ to $\operatorname{Spec}B$ to a morphism from this thickening.
For an algebraic field extension $L/K$ one can show that $K\to L$ is formally unramified if and only if it is formally smooth if and only if $L/K$ is separable. Cf. Problem 27 and [ M2 ] §25, §26 (where the discussion is extended to the general, not necessarily algebraic, case).
Let $f\colon A\to B$, $g\colon B\to C$ be ring homomorphisms. Then we obtain a natural sequence of $C$-modules
which is exact.
If moreover $g$ is formally smooth, then the sequence
is a split short exact sequence.
May 20,
2019
Let $f\colon A\to B$, $g\colon B\to C$ be ring homomorphisms. Assume that $g$ is surjective with kernel ${\mathfrak b}$. Then we obtain a natural sequence of $C$-modules
where the homomorphism ${\mathfrak b}/{\mathfrak b}^2 \to \Omega _{B/A}\otimes _BC$ is given by $x\mapsto d_{B/A}(x)\otimes 1$.
If moreover $g\circ f$ is formally smooth, then the sequence
is a split short exact sequence.
We can use a similar definition as we used for ring homomorphisms above to define the notions of formally unramified, formally smooth and formally étale morphisms of schemes.
We say that $f$ is formally unramified, if for every ring $C$, every ideal $I$ with $I^2=0$, and every morphism $\operatorname{Spec}C\to Y$ (which we use to view $\operatorname{Spec}C$ and $\operatorname{Spec}C/I$ as $Y$-schemes), the composition with the natural closed embedding $\operatorname{Spec}C/I\to \operatorname{Spec}C$ yields an injective map $\operatorname{Hom}_Y(\operatorname{Spec}C, X) \to \operatorname{Hom}_Y(\operatorname{Spec}C/I, X)$.
We say that $f$ is formally smooth, if for every ring $C$, every ideal $I$ with $I^2=0$, and every morphism $\operatorname{Spec}C\to Y$, the composition with the natural closed embedding $\operatorname{Spec}C/I\to \operatorname{Spec}C$ yields a surjective map $\operatorname{Hom}_Y(\operatorname{Spec}C, X) \to \operatorname{Hom}_Y(\operatorname{Spec}C/I, X)$.
We say that $f$ is formally étale, if $f$ is formally unramified and formally smooth.
If $f$ is a morphism of affine schemes, then $f$ has one of the properties of this definition if and only if the corresponding ring homomorphism has the same property in the sense of our previous definition.
Every monomorphism of schemes (in particular: every immersion) is formally unramified.
Let $A\to B\to C$ be ring homomorphisms such that $A\to B$ is formally unramified. Then we can naturally identify $\Omega _{C/A} = \Omega _{C/B}$.
Let $X\to Y$ be a morphism of schemes, and let ${\mathscr M}$ be an ${\mathscr O}_X$-module. A derivation $D\colon {\mathscr O}_X\to {\mathscr M}$ is a homomorphism of abelian sheaves such that for all open subsets $U\subseteq X$, $V\subseteq Y$ with $f(U)\subseteq V$, the map ${\mathscr O}(U)\to {\mathscr M}(U)$ is an ${\mathscr O}_Y(V)$-derivation.
Equivalently, $D\colon {\mathscr O}_X\to {\mathscr M}$ is a homomorphism of $f^{-1}({\mathscr O}_Y)$-modules such that for every open $U\subseteq X$, the Leibniz rule
holds.
We denote the set of all these derivations by $\operatorname{Der}_Y({\mathscr O}_X, {\mathscr M})$; it is a $\Gamma (X, {\mathscr O}_X)$-module.
May 22,
2019
There exists a unique ${\mathscr O}_X$-module $\Omega _{X/Y}$ together with a derivation $d_{X/Y}\colon {\mathscr O}_X\to \Omega _{X/Y}$ such that for all affine open subsets $\operatorname{Spec}B = U\subseteq X$, $\operatorname{Spec}A = V\subseteq Y$ with $f(U)\subseteq V$, $\Omega _{X/Y} = \widetilde{\Omega _{B/A}}$ and $d_{X/Y|U}$ is induced by $d_{B/A}$.
$\Omega _{X/Y} = \Delta ^*({\mathscr J}/{\mathscr J}^2)$, where $\Delta \colon X\to X\times _YX$ is the diagonal morphism, $W\subseteq X\times _YX$ is open such that $\mathop{\rm im}(\Delta )\subseteq W$ is closed (if $f$ is separated we can take $W=X\times _YX$), and ${\mathscr J}$ is the quasi-coherent ideal defining the closed subscheme $\Delta (X) \subseteq W$. The derivation $d_{X/Y}$ is induced, on affine opens, by the map $b\mapsto 1\otimes b-b\otimes 1$.
The quasi-coherent ${\mathscr O}_X$-module $\Omega _{X/Y}$ together with $d_{X/Y}$ is characterized by the universal property that composition with $d_{X/Y}$ induces bijections
\[ \operatorname{Hom}_{{\mathscr O}_X}(\Omega _{X/Y}, {\mathscr M}) \overset {\sim }{\to }\operatorname{Der}_{Y}({\mathscr O}_X, {\mathscr M}) \]for every quasi-coherent ${\mathscr O}_X$-module ${\mathscr M}$, functorially in ${\mathscr M}$.
The properties we proved for modules of differentials can be translated into statements for sheaves of differentials:
We start by slightly rephrasing the definition of a smooth morphism.
A morphism $f\colon X\to Y$ of schemes is called smooth of relative dimension $d\ge 0$ in $x\in X$, if there exist affine open neighborhoods $U \subseteq X$ of $x$ and $V=\operatorname{Spec}R\subseteq Y$ of $f(x)$ such that $f(U) \subseteq V$ and an open immersion $j \colon U \to \operatorname{Spec}R[T_1, \dots , T_n](f_1, \dots , f_{n-d})$ such that the triangle
is commutative, and that the images of $df_1$, …, $df_{n-d}$ in the fiber $\Omega _{\mathbb {A}^n_R/R}^1\otimes \kappa (x)$ are linearly independent over $\kappa (x)$. (We view $x$ as a point of $\mathbb {A}^n_R$ via the embedding $U \to \operatorname{Spec}R[T_1, \dots , T_n](f_1, \dots , f_{n-d}) \to \operatorname{Spec}R[T_1, \dots , T_n] = \mathbb {A}^n_R$.)
May 27,
2019
We skip the proof that smoothness implies formal smoothness, see for instance [ Bo ] Ch. 8.5. (But cf. the previous proposition which shows that a smooth morphism is at least “locally formally smooth”.)
May 29,
2019
Projective schemes
References: [ GW ] , Ch. 8, Ch. 11, in particular Example 11.43, (8.5); [ H ] II.6, II.7.
Let $R$ be a ring. We cover $\mathbb {P}^n_R$ by the standard charts $U_i := D_+(T_i)$, as usual, and write $U_{ij} := U_i\cap U_j$. For $d\in \mathbb {Z}$, the elements $(T_i/T_j)^d \in \Gamma (U_{ij}, {\mathscr O}_{\mathbb {P}^n_R})^\times $ define isomorphisms ${\mathscr O}_{U_i|U_{ij}}\to {\mathscr O}_{U_j|U_{ij}}$ which give rise to a gluing datum of the ${\mathscr O}_{U_i}$-modules ${\mathscr O}_{U_i}$. By gluing of sheaves, we obtain a line bundle ${\mathscr O}_{\mathbb {P}^n_R}(d)$. (Cf. Problems 9, 10.)
Now let $R=k$ be a field.
The closed subscheme $V_+(T_0)$ is a Weil divisor on $\mathbb {P}^n_k$, and it corresponds to the Cartier divisor $(U_i, T_0/T_i)_i$. The corresponding line bundle is ${\mathscr O}(1)$. By passing to multiples/negatives of this divisor, we can describe all ${\mathscr O}(d)$ in a similar way.
June 3,
2019
June 5,
2019
As we have seen last term, every scheme $X$ defines a contravariant functor $T\mapsto X(T):=\operatorname{Hom}_{\textup{(Sch)}}(T, X)$ from the category of schemes to the category of sets. This functor determines $X$ up to unique isomorphism. In this section, we want to describe the functor attached in this way to projective space $\mathbb {P}^n_R$ for $R$ a ring.
Note that a homomorphism $\alpha \colon {\mathscr O}_S^{n+1}\twoheadrightarrow {\mathscr L}$ corresponds to $n+1$ global sections in $\Gamma (S, {\mathscr L})$ (the “images of the standard basis vectors”). Thus $T_0, \dots , T_n\in \Gamma (\mathbb {P}^n_R, {\mathscr O}(1))$ give rise to a (surjective) homomorphism ${\mathscr O}_{\mathbb {P}^n_R}^{n+1}\to {\mathscr O}(1)$. Given a morphism $S\to \mathbb {P}^n_R$, we can pull this homomorphism back to $S$ and obtain an element of the right hand side in the statement of the proposition.
Conversely, given a pair $({\mathscr L}, \alpha )$ on $S$, we can think of the corresponding morphism $S\to \mathbb {P}^n_R$ in terms of homogeneous coordinates (i.e., for $K$-valued points for some field $K$), as follows: Denote by $f_0, \to f_n\in \Gamma (S, {\mathscr L})$ the global sections corresponding to $\alpha $. For a point $x\in S$, the fiber ${\mathscr L}(x)$ is a one-dimensional $\kappa (x)$-vector space generated by the elements $f_0(x), \dots , f_n(x)$ (i.e., at least one of them ins $\ne 0$ – this holds since $\alpha $ is surjective). We choose an isomorphism ${\mathscr L}(x) \cong \kappa (x)$, and hence can view the $f_i(x)$ as elements of $\kappa (x)$. Then the morphism $S\to \mathbb {P}^n_S$ maps $x$ to $(f_0(x) : \cdots : f_n(x)) \in \mathbb {P}^n(\kappa (x))$. While the individual $f_i(x)$, as elements of $\kappa (x)$, depend on the choice of isomorphism ${\mathscr L}(x)\cong \kappa (x)$, the point $(f_0(x) : \cdots : f_n(x)) \in \mathbb {P}^n(\kappa (x))$ is independent of this choice.
Reference: [ GW ] Ch. 13.
A graded ring is a ring $A$ with a decomposition $A = \bigoplus _{d\ge 0}A_d$ as abelian groups such that $A_d\cdot A_e\subseteq A_{d+e}$ for all $d, e$. The elements of $A_d$ are called homogeneous of degree $d$.
Let $R$ be a ring. A graded $R$-algebra is a graded ring $A$ together with a ring homomorphism $R\to A$.
A homomorphism $A\to B$ of graded rings (or graded $R$-algebras) is a ring homomorphism (or $R$-algebra homomorphism, respectively) $f\colon A\to B$ such that $f(A_d)\subseteq B_d$ for all $d$.
Let $A$ be a graded ring. A graded $A$-module is an $A$-module $M$ with a decomposition $M=\bigoplus _{d\in \mathbb {Z}} M_d$ such that $A_d\cdot M_e\subseteq M_{d+e}$ for all $d, e$. The elements of $M_d$ are called homogeneous of degree $d$.
A homomorphism $M\to N$ of graded $A$-modules is an $A$-module homomorphism $f\colon M\to N$ such that $f(M_d)\subseteq N_d$ for all $d$.
Let $A$ be a graded ring and let $M$ be a graded $A$-module. A homogeneous submodule of $M$ is a submodule $N\subseteq M$ such that $N = \bigoplus _{d\in \mathbb {Z}} (N\cap M_d)$. In this way, $N$ is itself a graded $A$-module and the inclusion $N\hookrightarrow M$ is a homomorphism of graded $A$-modules. (And conversely, every injective homomorphism of graded $A$-modules has a homogeneous submodule as its image.) A homogeneous submodule of $A$ is called a homogeneous ideal.
We now fix a graded ring $A$.
For a homogeneous element $f\in A_e$, and a graded $A$-module $M$, the localization $M_f$ is a graded $A$-module via
Applying this to $A$ as an $A$-module, we obtain a grading on $A_f$ giving $A_f$ the structure of a graded ring. Then $M_f$ is a graded $A_f$-module.
We define
the degree $0$ part of $M_f$. Then $A_{(f)}$ is a ring and $M_{(f)}$ is an $A_{(f)}$-module.
For a homogeneous element $f$, we write $D_+(f) := \operatorname{Proj}(A)\setminus V_+(f)$.
June 17,
2019
Let $A$ be a graded ring, $X=\operatorname{Proj}A$. If $M$ is a graded $A$-module, there is a unique sheaf $\widetilde{M}$ of ${\mathscr O}_X$-modules such that
for every homogeneous element $f\in A$, and such that the restriction maps for inclusions of the form $D_+(g)\subseteq D_+(f)$ are given by the natural maps between the localizations. This sheaf is a quasi-coherent ${\mathscr O}_X$-module.
Let $A(n)$ be the graded $A$-module defined by $A(n) = \bigoplus _{d\in \mathbb {Z}} A_{n+d}$. We set ${\mathscr O}_X(n) = \widetilde{A(n)}$. If $A=R[T_0, \dots , T_n]$ for a ring $R$, so that $X=\mathbb {P}^n_R$, then this notation is consistent with our previous definition.
For $f\in A_d$, multiplication by $f^k$ defines an isomorphism
In particular, if $A$ is generated as an $A_0$-algebra by $A_1$, then ${\mathscr O}_X(n)$ is a line bundle.
Assume, for the remainder of this section, that $A$ is generated as an $A_0$-algebra by $A_1$. So $X = \bigcup _{f\in A_1} D_+(f)$, and ${\mathscr O}_X(n)$ is a line bundle.
For an ${\mathscr O}_X$-module ${\mathscr F}$, write ${\mathscr F}(n) :={\mathscr F}\otimes _{{\mathscr O}_X}{\mathscr O}_X(n)$, and define a graded $A$-module $\Gamma _*({\mathscr F})$ by
Call a graded $A$-module $M$ saturated, if the map $M\to \Gamma _*(\widetilde{M})$ is an isomorphism.